BlueCruiser84
SILVER Star
I hear ya Methusalem...
Think of it this way... if you cut all the tread off a 33 inch tire and then cut all the tread off a 33.5 inch tire you would have two strips of tread. The one from the 33 (assuming it is a true 33) would be 103.673 inches long. The tread strip from the 33.5 inch tire would be 105.243 inches long. These strips of tread represent the distance traveled by one rotation of your tire. Obviously one travels further than the other causing the locker to unload or bind. Just because you change the PSI in the 33.5 inch tire doesn't mean that strip of tread will shrink.
Deflate the 33 inch tire to 0 PSI so the rim goes down an inch from the ground. This leaves a distance of 8.5 inches from the center of the hub. Assuming the tire stays on the bead, by Mace's and Rusty's theories that means that with one revolution of the wheel the tire will only travel 26.704 inches. But we know that is not the way it works.
It's the same thing as running different sized tires on the front and rear of a 4x4 vehicle (with the same gears in the axles). If you don't have any slip the transfer case (which is essentially a locked diff) will bind.
Think of it this way... if you cut all the tread off a 33 inch tire and then cut all the tread off a 33.5 inch tire you would have two strips of tread. The one from the 33 (assuming it is a true 33) would be 103.673 inches long. The tread strip from the 33.5 inch tire would be 105.243 inches long. These strips of tread represent the distance traveled by one rotation of your tire. Obviously one travels further than the other causing the locker to unload or bind. Just because you change the PSI in the 33.5 inch tire doesn't mean that strip of tread will shrink.
Deflate the 33 inch tire to 0 PSI so the rim goes down an inch from the ground. This leaves a distance of 8.5 inches from the center of the hub. Assuming the tire stays on the bead, by Mace's and Rusty's theories that means that with one revolution of the wheel the tire will only travel 26.704 inches. But we know that is not the way it works.
It's the same thing as running different sized tires on the front and rear of a 4x4 vehicle (with the same gears in the axles). If you don't have any slip the transfer case (which is essentially a locked diff) will bind.
) would be right if the tire was not connected with the rim. Then the rim would just roll over the inside of the tire and not use the whole radius of the tire with one cycle of the smaller spare at the other side.
... mechanical engineer maybe
So now I translate books, live in a relaxter country and bought a Cruiser. Live's good and God even better
