So 1.1 A is flowing through the meter and bypassing the fusible link.
I think this meter DOES affect the circuit it is "testing" then.
If you think of it as a millivoltmeter (and sorry to revert to that), then I think when it's drawing 1.1A it will be lowering the voltage drop across the fusible link.
In other words, if you were to disconnect the ammeter/millivoltmeter, I think the voltage drop across the fusible link would rise by a significant percentage.
Actually no, probably not that much.
To explain why in a rigorous way would force me to write a very long post, which would expose me as the insufferable pedant that I am. Plus you probably wouldn't read the whole thing anyway.

I'll just present the math - @50A through the circuit, with a proper 0.006 ohm shunt (18"), connecting the .27ohm meter across the shunt will drop the shunt voltage by only 3%.
With a "OEM" shunt (about 3") its more like 4%.
EDIT:
Also - keep in mind that this effect is already "calibrated in" to the gauge - the markings are positioned accordingly.
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