I used the Supra CT26. I will help you understand, first you need to know the displacement of the subject engine in cubic inches. You will then need to know the RPM of said engine. Efficiency is a constant .85 .0.5 is for a 4 stroke engine.
1728 is a cubic foot. You then take the end number and multiply that times the forced induction ratio. Pressure ratio= 14.7+ boost divided by 14.7.
There you go!
eric
That approach will always give you the wrong answer. There is no such thing as a "forced induction ratio". You must use the air density ratio.
This requires knowledge of the inlet conditions (pressure and temp) along with an understanding of adiabatic compression and a map of the compressor efficiency.
Here is the process to find your density ratio, this example was posted up by me on 4btswaps.com on feb 16th last year. PR is 2.25 which is boost of roughly 18psi.
1. Start with intake conditions, pressure, temperature, density. Use PV=NRT to ensure you know all relevant conditions. Work in absolute temperature (Kelvin scale), My conditions are for temp 293K; pressure 101.3 kPa and air density of 1.2 kg/m^3
2. Find your pressure ratio, in this case 2.25
3. Apply adiabatic compression to find the outlet temperature relating to a 100% adiabatic compression. T2/T1 = compression^(gamma-1/gamma).
Gamma is 1.4 for air. Tout = 369.4K
4. Find the adiabatic temperature rise. This is your adiabatic outlet temp (369.4-273=76.4K) your adiabatic outlet temp.
5. Divide this temp rise by your compressor efficiency (0.65 in this case). This gives you your actual outlet temperature. (76.4/0.65+273 = 410.5K)
6. Use PV=nRT to find the the volume (and density) of the output charge using your pressure ratio and your actual outlet temp and density. Density = 1.93, intake density =1.2
density ratio =(1.93/1.2=1.61)
7. Divide original density by resulting density to get the density ratio. 1.2/1.93 = 1.61