Charge Ckt

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Where exactly are you suggesting? I'm not sure where the sense wire is (I thought this was it). I searched the EWD for "sense" before I left for work, and nothing came up.

Sense is the "S" wire on the schematic.

What location are you putting the diode? Engine Bay Fuse Block or Dash Fuse Block?
 
It appears the 100 series puts a 7.5A fusiable link in front of the alternators Sense wire. According to instructions, it is this fuse that gets replaced by the diode.

On the 80 series, the fuse location, 7.5A Charge, is on the Charge Light Warning circuit. It is not on the Sense Line circuit.

You could add the diode to where the Sense line connects at the FL AM1 1. 2 5B near the battery. Just add an inline fuse holder.
 
You could add the diode to where the Sense line connects at the FL AM1 1. 2 5B near the battery. Just add an inline fuse holder.
I don't think I would go that route as FL AM1 feeds a variety of downstream circuits so you would need a diode that can handle the current.
I would install it close to the alternator if I would do this at all, which I would not.

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I wonder why it's a diode at all. Just because it can be had in the form factor of a fuse? I can't imagine what the directionality of the diode would have to do with anything here... seems it's just the resistive effect in the right direction... so would a resistor do the same thing?

I don't think I'll experiment any further with this. I do have to rip out the entire charging system to crimp the connectors, so maybe I'll redo some of that wiring, if I identify something to change, I'll do it at the same time.

That leaves me back at square one. What little searching I could do for custom/adjustable regulators, today, yielded nothing of value. Happy to hear any input or advice.
 
Only 1 of the two circuits will be available. You probably only have circuit *1, unless you have daytime running lights.

View attachment 4108433
I'm sure you think I'm an idiot. I did a search for "Canada", this morning, and then realized I couldn't find this detail because the Adobe "find" window was covering it!
 
I'm sure you think I'm an idiot. I did a search for "Canada", this morning, and then realized I couldn't find this detail because the Adobe "find" window was covering it!

No worries. 😉 We all miss things.

It is just something I came across previously when studying Toyota EWDs.
 
I wonder why it's a diode at all. Just because it can be had in the form factor of a fuse? I can't imagine what the directionality of the diode would have to do with anything here... seems it's just the resistive effect in the right direction... so would a resistor do the same thing?

I don't think I'll experiment any further with this. I do have to rip out the entire charging system to crimp the connectors, so maybe I'll redo some of that wiring, if I identify something to change, I'll do it at the same time.

That leaves me back at square one. What little searching I could do for custom/adjustable regulators, today, yielded nothing of value. Happy to hear any input or advice.
It's a diode because the diode has a voltage drop in the forward direction that is likely around 0.5 to 0.7V. So, it basically would make the sense voltage look 0.5 to 0.7V lower than it actually is. So, the regulator will increase the alternator voltage by 0.5 to 0.7V to get it to the voltage it wants to regulate to. So, the diode in effect will increase the charge voltage to the battery by 0.5 to 0.7V.

There's companies that sell this magic diode thing for many dollars...

It is a hack.

cheers,
george.
 
It's a diode because the diode has a voltage drop in the forward direction that is likely around 0.5 to 0.7V. So, it basically would make the sense voltage look 0.5 to 0.7V lower than it actually is. So, the regulator will increase the alternator voltage by 0.5 to 0.7V to get it to the voltage it wants to regulate to. So, the diode in effect will increase the charge voltage to the battery by 0.5 to 0.7V.

There's companies that sell this magic diode thing for many dollars...

It is a hack.

cheers,
george.
But my point is that V drop can be created with a resistor.
 
But my point is that V drop can be created with a resistor.
It absolutely can, and would be cleaner if wired in the harness for the sense wire.

The diode thing exists simply as a plug n play alternative for the masses. Most folks can't solder and crimp, but they can handle swapping a fuse for a diode from a GM that simply plugs in and works.

This makes me want to order some connectors and make a plug n play harness that goes between the factory harness and the alternator and experiment...
 
It absolutely can, and would be cleaner if wired in the harness for the sense wire.

The diode thing exists simply as a plug n play alternative for the masses. Most folks can't solder and crimp, but they can handle swapping a fuse for a diode from a GM that simply plugs in and works.

This makes me want to order some connectors and make a plug n play harness that goes between the factory harness and the alternator and experiment...
Thats what I thought. I'd do the same, but my electronics skills are too faded to be messing with this expensive equipment.
 
NO - a resistor has a voltage drop dependent on the current through it. How would you choose the resistor value in this case? What current would be flowing through it? V = I * R. What is the I in this case?? A resistor is NOT what you want to use in this application.

A diode has a relatively fixed voltage drop that is mostly independent on current through it, certainly minimal difference between say 100uA and 100mA. Of course there will be temperature dependence and some current dependence. It is a hack.

There are different types of diodes (silicon, schottky etc). A silicon diode will be in the 0.5 to 0.7V range. A schottky closer to 0.2V to 0.5V. You can also put diodes in series. The issue is that the voltage drop is not very precise. It is a hack...

cheers,
george.
 
NO - a resistor has a voltage drop dependent on the current through it. How would you choose the resistor value in this case? What current would be flowing through it? V = I * R. What is the I in this case?? A resistor is NOT what you want to use in this application.

A diode has a relatively fixed voltage drop that is mostly independent on current through it, certainly minimal difference between say 100uA and 100mA. Of course there will be temperature dependence and some current dependence. It is a hack.

There are different types of diodes (silicon, schottky etc). A silicon diode will be in the 0.5 to 0.7V range. A schottky closer to 0.2V to 0.5V. You can also put diodes in series. The issue is that the voltage drop is not very precise. It is a hack...

cheers,
george.
Makes sense, thanks.
 
Got the expected 0.5V increase in charge. Time will tell if this works or not. This was on a cold start so the alternator was already cranking out 14.1V, where when it's warmed up I usually only see 13.6-13.8. Immediate shutdown, and then I plugged in my little patch harness between the alternator and the factory harness. Restarted 2 mins later, and got the 0.5V bump. Diode is on the sense wire at the alternator. YMMV

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What's in the fuse holder? The GM diode? Did you try turning on all the stuff shown in post 24 to see what happens?
Yes, GM diode in the fuse holder. So far, no ill effects- even with all accessories powered up. The diode is only on the sense wire at the alternator, so in theory nothing else should care.
 
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