Yes...I guess it’s a multi part question...
the first part is: is it technically torque being transferred? Is there another word for what is transferred across axle when a traction system brakes a free spinning wheel in order to give traction to a non spinning wheel?
and that question is only so we don’t get lost in terminology issues...
The second part is: whatever is being transferred...is it 100% of the available amount or 50% when you completely arrest the movement of the spinning wheel?
And the third part is, if you locked the axle thereby not requiring the transfer of whatever that was that was transferred initially...is each wheel then receiving 50% each of that stuff?
the relevance being, if you completely arrest the spinning of one tire, and thereby send 100% of the available stuff (torque or whatever) to the wheel across the axle, are you actually doubling the stuff (torque) on the other wheel?
I think first I need the terminology though...I call it torque but it appears people are saying it’s something else. Once I know what it is, the questions are less unwieldy.
with an open diff, you're sending 100% of torque to the diff. the diff is then sending 100% of power to the "least grippy" wheel. If both wheels have grip, then they get ~50/50 distribution, but for instance in a turn the outer wheel taking the longer path gets a higher percentage than the inner wheel.
1. braking the spinning wheel is just friction (or "negative acceleration" if you prefer - as I said, IANAP, I just play one). in an open diff
2. In an
open diff, you send 100% of torque to the non-braked wheel
once it can move freely. Note the last part as while the brake is applied to one wheel and the other is in contact with the ground and has traction, *temporarily* you've got the equivalent of both wheels having "grip" (resistance, really) so the torque being sent down the driveshaft and into the diff is getting spread across both shafts. It's only once the tire starts to move (either because it has traction or because it
loses traction and then spins freely) that >50% torque is being directed to that side.
3. Note this is in contrast to a
locked diff where torque is applied to any wheel that has contact. If both wheels are on the ground then each one gets 50% of the torque. If one is in the air and one is on the ground, then the wheel in the air spins, but it doesn't take much force to move it so the physics effect is that all of the torque from the driveline is being directed to the wheel on the ground, thus giving the wheel with traction 100% of available torque.
(Side note, which I think applies to your "relevance" question: if ATRAC/MTS is braking your wheel that's high up in the air then that side is in fact receiving some of the force from your driveline so 100% of torque is not being applied just to the wheel on the ground (though it may still be >50% - so if you use lockers you want to turn off ATRAC/MTS if possible)
Remember torque is the twisting force. It has nothing to do with the speed of the twist (that's RPMs), or how quickly you get there (that's determined by HP). Think about using a screwdriver. On a loose screw it requires very little effort to twist the screwdriver and push the screw in. You might even be able to do it with your fingers. That's low torque. However if the screw is nearly stuck (like you used a 3" long screw in a piece of solid oak and didn't drill a pilot hole) then it takes a LOT of (slow) force for you to twist the screw in without stripping it.