ElJefe said:
The expiditions west article is saying that a PROPERLY INFLATED narrow tire will have a smaller contact patch than a properly inflated wide tire on the same vehicle because the pressure will be much higher in the narrow tire at proper inflation.
The expiditions west article says, and I quote
"For the sake of the following details, assume that the test vehicle is 5,000 lbs., and a narrow tire would be considered a 33x10.5 R15, and a wide tire would be considered a 33x12.5 R15, both run at 15psi for trail use. "
Idaho Doug is right. and all of this is wrong...
From the expeditions west site
“A wide tire distributes the vehicles weight over too large of a surface”
e9999 said:
keep in mind a skinnier tire will have higher pressure on the ground, therefore be more likely to be punctured or damaged, everything else the same...
Kalawang said:
Skinny tires have less rubber on the road
The diagram on the Expeditions West site is wrong, or at least incomplete, because it is only looking at one dimension of the contact patch - the width. It's ignoring the length of the contact patch. It says that the skiner tire conforms more to the spikes because it needs to to make up the difference from 3 spikes to the wide tires 5 spikes. It's not so much that the contact patches have to be wider, as is shown, it's that they get longer. They may get wider too on the skinner tire, but alot of that will have to do with the shape of the rocks (spikes in the diagram), and the construction of the tire ect. ect.
Anyway - if running the same pressure, skinny vs. wide, the shape of the contact patch changes from a tall rectangle to a wide one, like Doug said, and the direction of greatest traction changes from forward to sideways. Take a piece of sand paper that is 2" wide and 8" long, try pushing it the long way, or push it the short way, you'll feel the difference.
It doesn't make all the other arguements wrong, just those assuming you have more contact patch with a wider tire at the same inflation pressure.
Here's another from the article that didn't sit right....
"To ease the description, let's assume that the test vehicle weights 5,000 lbs and has a perfect weight distribution. Each of the vehicles four tires would be creating 1,250 lbs. of vertical pressure on the terrain. Let's assume for the sake of this example that the vehicles tires are 10” wide, where the load and tire pressure results in a total surface area of 30 sq. inches. The total pressure per square inch (without equating the secant) would equal 40 lbs"
It's an odd way of coming to the conclusion that the tire is at 40psi. A cleaner way of saying it is - tires are 10" wide, 1250lbs on each tire, the contact area is going to be the weight, 1250 lbs, divided by the PSI 40 (lbs/sq-in) or 31.25sq-in. For a tire that is 10" wide, the contact patch will be 3.125" long. For a tire that is 12.5" wide the contact patch will be 2.5" long, by 12.5" wide. This is the difference in shape that Idaho Doug is talking about.
Another way to look at it (as if we need another), is if you put a 33 x 10.50 and a 33 x 12.5 on the same vehicle, and space them out to compensate for the track width, and then you put in on a plate, that you could tilt side to side and fore to aft. As you raised the front of the ramp, the wider tire would loose traction and start to slide back first. As you tilted the ramp to the side, the narrower tire would loose traction and start to slide sideways first.
from here:
http://www.tirerack.com/tires/tiretech/techpage.jsp?techid=10