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07-04-09, 06:54 PM
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#61 (permalink)
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250+ Club
Join Date: Jul 2006
Location: hillbilly desert rat
Posts: 381
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you just had to bring her up.... WWWWWWWWWWWWWWAAAAAAAAAAAAAAAAAA
__________________
91 running 33 toyo mt's hillbilly roof rack,air lockers,Tube bumper,breaking stuff too..
custom dog tags for sale GI style or for pets $5 includes shipping
I don't give a damn for a man that can only spell a word one way.
decavo's custom jewelry ,vegan soaps, lip balm, lotions all natural products
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07-04-09, 08:39 PM
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#62 (permalink)
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I can mangle anything...
Join Date: Jan 2005
Location: BTR, PHX, OMA
Posts: 2,304
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Quote:
Originally Posted by decavo
you just had to bring her up.... WWWWWWWWWWWWWWAAAAAAAAAAAAAAAAAA
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Quote:
Originally Posted by decavo
I am always using math to calculate formulas and pricing of my products, but put a "x" in there and I am freaking out.,,
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 you typed "x" 
__________________
Claudia
'72FJ40 with a no-number 2F, MAF headers, 4spd, 33x10.5 BFG MT, 4" lift, roll cage, prehistoric ARB lockers f/r, MAF disk brakes f/r, hand throttle, Painless wiring, CB, custom horn brush, dual advance dizzy, Bilsteins, 4+ front bumper/rear shackles/U-bolt flip, Kevin-improved frame/shackles/shackle hanger, several polished turds  , with ChaseTruck  yes, MANUAL steering 
Copper State Cruisers #40
http://www.desertrider.net/
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07-04-09, 08:56 PM
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#63 (permalink)
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Forum Regular
Join Date: Nov 2004
Posts: 98
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ya might as well give it up.
ya don't have the brains.
might as well go to law school or join the military. ya too stoopid for anything else.
__________________
LC newbie
Proud daddy of 3 boys and
85 FJ60, stock, 31" tires, 2" lift, RUSTY but runs, and
LX450, locked, Slee front bumper, DD
"The beatings will continue until morale improves!"
- an old Parris Island slogan.
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07-05-09, 02:12 AM
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#64 (permalink)
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Site Addict
Join Date: Oct 2005
Location: Rolla, MO (UMR)
Posts: 1,988
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Quote:
Originally Posted by carboncycles
decavo, what you are trying to do is called "completing the square"
Completing the Square: Solving Quadratic Equations
The guys giving you advice were right, but IMO didn't explain it correctly.
So, what you wanted to do is take advantage of the some basic algebraic identities, and for you to do that, you have to take your original equation and put them in the right form.
So, your equation was setup as:
x^2 + 4x...
1) To complete the square, we take the 4 from the 4x
2) Divide the 4 by 2...this gives 2
3) Then we square the 2..this gives us the 4, which we also need to add to the other side of the "=" sign.
See the link above as it has some more examples that you can look at it.
Good luck and stick with it...next semester it will be calculus  |
Ding ding ding........I actually know how to do this.
If you have a equation like
ax(sq)+bx+c=0 and it won't factor. You can move the 'c' to the right side of the equation using the simple '-c'(I assume you know how to do this).
Now you divide 'b' by 2, then square it. That assures you have a
"complete square" to factor with.
So you can end up with an (x+/-something)(x+/-something else)=a number.
Then you solve for the two x's, using whatever method you want, I like a calculator with a solver program. Remember you will get two solutions. It is possible that one of the solutions will not make sense in the context of the problem....ie| A train leaves the station etc.....when does it arrive at station b? A negative answer here will not make sense so you end up with only one correct solution.
lunyou
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07-05-09, 02:21 AM
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#65 (permalink)
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250+ Club
Join Date: Nov 2005
Location: Visalia, CA
Posts: 510
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Quote:
Originally Posted by decavo
I hope that light comes on soon.
I am always using math to calculate formulas and pricing of my products, but put a "x" in there and I am freaking out.,,
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"X" stands for "A placeholder for something I don't know yet," and the information you need to convert X from "placeholder" to "known quantity" is always there. Algebra can be thought of as the rules and processes that enable you to make the conversion.
Keep in mind that algebra is a symbolic language, and some people's brains simply are not wired to deal in abstraction. Handling abstraction is a particular type of intelligence, like high empathy or natural musical talent. Some people have it and some people don't, so for some people algebra comes naturally, and for others it comes with a lot of hard work, if at all.
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07-05-09, 10:37 AM
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#66 (permalink)
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Forum Lifer
Join Date: Feb 2006
Posts: 9,481
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lol...Lunyou with the pain
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07-05-09, 01:19 PM
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#67 (permalink)
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Drinking the Kool-aid
Join Date: Aug 2006
Location: On a darkling plain
Posts: 234
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Quote:
Originally Posted by cruiser88
lol...Lunyou with the pain
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except that it appears to be wrong.
Quote:
Originally Posted by Creeker
Dammit, look: put your formula in the form of
then solve for x:
x= 
don't ask why it works, just memorize the fricking formula. It's a basic algebraic formula and I don't think anyone's going to ask you to prove it unless you're doing some "beautiful mind" math. |
Once again, use the quadratic equation. Solving for x:
x^2+4x+1=0
a=1, b=4, c=1
x= [-4+/- square root (4^2-4(1)(1))]/2(1)
x=-3.732 or -.268
plug either of those numbers back into your original equation and they both work. Does anyone else have a value for x that works in the original equation? Any other approach will have to be the long way around to arrive at the quadratic equation, or else it won't work.
__________________
'88 FJ62 - 12HT conversion, OME Lift, ARB front bumper, Roof Rack
'04 Prius - stock
'66 Pearson Commander - a hole in the water to throw money into.
__________________________________________________ ________________________________________
And we are here as on a darkling plain
Swept with confused alarms of struggle and flight,
Where ignorant armies clash by night.
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07-05-09, 01:32 PM
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#68 (permalink)
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Forum Lifer
Join Date: Feb 2006
Posts: 9,481
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lol..........I never even went through his post..I just thought it was funny
Quote:
Originally Posted by Creeker
except that it appears to be wrong.
Once again, use the quadratic equation. Solving for x:
x^2+4x+1=0
a=1, b=4, c=1
x= [-4+/- square root (4^2-4(1)(1))]/2(1)
x=-3.732 or -.268
plug either of those numbers back into your original equation and they both work. Does anyone else have a value for x that works in the original equation? Any other approach will have to be the long way around to arrive at the quadratic equation, or else it won't work.
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